A car moving with a velocity of 10m/s and with a uniform acceleration gains a velocity of 30m/s after traveling a distance of 4km then time taken is

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Solution

When an object travels in a straight line-

speed= velocity

avg speed=avg velocity

avg velocity = u+v/2
avg velocity = 10+30/2
=20m/s
Then we know that,

v×t=s
t = s / v
Here
v=20m/s
And
S= 4000 m
Therefore
t = s / v
=4000/20= 200 second

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A car moving with a velocity of 10m/s and with a uniform acceleration gains a velocity of 30m/s after traveling a distance of 4km then time taken is

When an object travels in a straight line- speed= velocity avg speed=avg velocity avg velocity = u+v/2 avg velocity = 10+30/2 =20m/s Then we know that, v×t=st = s / vHerev=20m/sAnd S= 4000 mThereforet = s / v=4000/20= 200 second

When an object travels in a straight line-

speed= velocity

avg speed=avg velocity

avg velocity = u+v/2
avg velocity = 10+30/2
=20m/s
Then we know that,

v×t=s
t = s / v
Here
v=20m/s
And
S= 4000 m
Therefore
t = s / v
=4000/20= 200 second