Question

A car moving with constant acceleration of$1.5m{s}^{-2}$ covers x m in $4s$ and $21m$ in the next $2s$. The initial velocity of the car is$3m{s}^{-1}$. Calculate the value of $x$

• A. $2.4m$
• B. $24cm$
• C. $24m$
• D. $21cm$

Answer 1

The correct option is C

$24m$

Step 1: Given data,

Initial acceleration= $1.5m{s}^{-2}$

Initial velocity$=3m{s}^{-1}$

Distance covered in $4$ second is$xm.$

Step 2: Explanation

Displacement is given by,

$s=$$ut+\frac{1}{2}a{t}^2$

Therefore for x,

$x=3\times 4+$ $\frac{1}{2}\times 1.5\times {\left(4\right)}^2$

x= 12+12 = 24 m.

Hence the correct option is (c) 24 m.