A car moving with initial velocity of $15 m s^{- 1}$ accelerates at the rate of $4 m s^{- 2}$ . What is the final velocity of the car after $10 s$ ?

65 m s^{- 1}

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55 m s^{- 1}

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70 m s^{- 1}

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40 m s^{- 1}

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Solution

The correct option is B $55 m s^{- 1}$
Given:
Initial velocity, $u = 15 m s^{- 1}$
Acceleration, $a = 4 m s^{- 2}$
Time taken, $t = 10 s$

Let the final velocity be v.

Using the first equation of motion,
$v = u + a t$
$v = 15 + (4 \times 10) = 55 m s^{- 1}$

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A car moving with initial velocity of 15 ms−1 accelerates at the rate of 4 ms−2. What is the final velocity of the car after 10 s?

The correct option is B 55 ms−1Given: Initial velocity, u=15 ms−1 Acceleration, a=4 ms−2 Time taken, t=10 s Let the final velocity be v. Using the first equation of motion, v=u+at v=15+(4×10)=55 ms−1

A car moving with initial velocity of $15 m s^{- 1}$ accelerates at the rate of $4 m s^{- 2}$ . What is the final velocity of the car after $10 s$ ?

The correct option is B $55 m s^{- 1}$
Given:
Initial velocity, $u = 15 m s^{- 1}$
Acceleration, $a = 4 m s^{- 2}$
Time taken, $t = 10 s$

Let the final velocity be v.

Using the first equation of motion,
$v = u + a t$
$v = 15 + (4 \times 10) = 55 m s^{- 1}$