A car moving with speed $30$ m/s on a circular path of radius $500$ m. Its speed is increasing at the rate of $2 m / s^{2}$ . The acceleration of the car is?

9.8 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.8 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.7 m / s^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2.7 m / s^{2}$
$V = 30 m / s$
$r = 500 m$
$a_{c} = \frac{v_{2}}{r}$
$\frac{30 \times 30}{500}$
$\frac{900}{500}$
increasing the rate
$a = \sqrt{a_{t} + a_{c}} = \sqrt{(2^{2}) + ({1.8}^{2})} \sqrt{4 + 3.24} = \sqrt{7.24} = a = 2.7$

Suggest Corrections

Similar questions

Q. A motor car is moving with speed 30m/s on a circular path of radius 500m. Its speed is increasing at the rate of

2 m / s^{2}

. What will be its resultant acceleration?

Q. A car is moving along a circular path of radius

500 m

with a speed of

30 m / s

. If at some instant, its speed increases at the rate of

2 m / s^{2}

, then at that instant, the magnitude of resultant acceleration will be

A car is moving with speed 30 m/sec on a circular path of radius 500 m.
Its speed is increasing at the rate of 2m/ $s e c^{2}$ , What is the acceleration of the car

Q. A car is travelling at 30 m/s on a circular road of radius 300m. It is increasing its speed at the rate of

4 m / s^{2}

. The acceleration of the car is .................

Q. A car is moving on a circular track of radius 100 m with a net acceleration of

7 m / s^{2}

. If the speed of the car is increasing at the rate of

5 m / s^{2}

, its speed is

Join BYJU'S Learning Program

A car moving with speed 30 m/s on a circular path of radius 500m. Its speed is increasing at the rate of 2m/s2. The acceleration of the car is?

The correct option is D 2.7m/s2V=30m/sr=500mac=v2r30×30500900500increasing the rate a=√at+ac=√(22)+(1.82)√4+3.24=√7.24=a=2.7

A car moving with speed $30$ m/s on a circular path of radius $500$ m. Its speed is increasing at the rate of $2 m / s^{2}$ . The acceleration of the car is?

The correct option is D $2.7 m / s^{2}$
$V = 30 m / s$
$r = 500 m$
$a_{c} = \frac{v_{2}}{r}$
$\frac{30 \times 30}{500}$
$\frac{900}{500}$
increasing the rate
$a = \sqrt{a_{t} + a_{c}} = \sqrt{(2^{2}) + ({1.8}^{2})} \sqrt{4 + 3.24} = \sqrt{7.24} = a = 2.7$