Question

A car of mass $1000kg$ moves on a circular track of radius $40m$. If the coefficient of friction is 1.28 then the maximum velocity with which the car can be moved is:

• A. $22.4m/s$
• B. $112m/s$
• C. $\frac{(0.64\times 40)}{(1000\times 100)}m/s$
• D. $1000m/s$

Answer 1

The correct option is A $22.4m/s$

The centripetal acceleration is provided by the frictional force acting on the car towards the center of the circular path followed.

Thus, $m\frac{v^2}{r}=\mu mg$

$⟹v=\sqrt{\mu gr}=\sqrt{1.28\times 10\times 40}$ $=22.4m/s$