Question

A car of mass 1000 kg moves uniformly at $10{ms}^{-1}$ . If the engine of the car develops an extra linear momentum of $1000k{ms}^{-1}$, calculate the new velocity with which the car runs.

• A. $22{ms}^{-1}$
• B. $11{ms}^{-2}$
• C. $55{ms}^{-1}$
• D. $11{ms}^{-1}$

Answer 1

The correct option is D $11{ms}^{-1}$

Solution : Initial mometum of the car $P_1=m\times v_1{P}_1=1000\times 10;P_1=10,000NsThusnewmomentumofthecar{P}_2=P_1+increaseinmomentum{P}_2=10,000+1000;P_2=11000Ns{P}_2=m\times v_{2}Where{v}_{2}isthenewvelocityofthecar\therefore 11000=1000\times v_2\Rightarrow v_2=\frac{11000}{1000}=11{ms}^{-1};v_2=11{ms}^{-1}$