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Question

A car of mass 1000 kg moving on a circular track of radius 100 m with increase in speed at a rate of 8 m/s2, if at an instant its speed is 30 m/s then the acceleration of the car is (at this instant only)

A
>12
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B
<12
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C
=12
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D
Noneofthese
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Solution

The correct option is C =12

Given that,

Mass m=1000kg

Radius r=100m

Speed v=30m/s

Tangential acceleration at=8m/s

Now,

Radial acceleration is

ar=v2r

ar=30×30100

ar=9m/s

The resultant acceleration is

a=a2t+a2r

a=82+92

a=64+81

a=12.04

a=12m/s2

Hence, the acceleration is 12m/s2


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