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Standard IX

Physics

Second Law of Motion

A car of mass...

Question

A car of mass 1000 kg travelling at 12 m/sec dashed into rear of bus of mass 2000 kg moving in same direction at 8 m/ sec . The car bounces backwards after collision with a speed of 9 m / sec. What is the recoil velocity of gun.

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Solution

By law of conservation of momentum
miu1+m2u2=m1v1+m2v2
m1=1000
m2=2000
u1=12
u2=8
v1=9
v2=?

So substituting values
100012+20008=10009+2000v2
12000+16000=9000+2000v2
28000-9000=2000v2
19000/2000=v2
9.5=v2

So 9.5m/s is the answer.

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A car of mass 1000 kg travelling at 12 m/sec dashed into rear of bus of mass 2000 kg moving in same direction at 8 m/ sec . The car bounces backwards after collision with a speed of 9 m / sec. What is the recoil velocity of gun.

By law of conservation of momentum miu1+m2u2=m1v1+m2v2 m1=1000 m2=2000 u1=12 u2=8 v1=9 v2=? So substituting values 1000*12+2000*8=1000*9+2000*v2 12000+16000=9000+2000v2 28000-9000=2000v2 19000/2000=v2 9.5=v2 So 9.5m/s is the answer.

By law of conservation of momentum
miu1+m2u2=m1v1+m2v2
m1=1000
m2=2000
u1=12
u2=8
v1=9
v2=?

So substituting values
100012+20008=10009+2000v2
12000+16000=9000+2000v2
28000-9000=2000v2
19000/2000=v2
9.5=v2

So 9.5m/s is the answer.