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Question

A car of mass 1000 kg is moving with the speed 40 m/s on a circular path of radius 400 m. If its speed is increasing at the rate of 3 ms−2 the total force acting on the car is

A
3000 N
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B
4000 N
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C
5000 N
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D
7000 N
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Solution

The correct option is C 5000 N
We know that, the net force Fnet=manet.
Here the car is moving in the circular path and hence there will be two type of acceleration, tangential and centripetal acceleration which are perpendicular to each other.

Hence the net acceleration
anet=(v2rg)2+(aT)2, it is given that the speed is increasing at the rate of 3 m/s2, so aT=3 m/s2.

Hence the net force,
Fnet=manet=m(v2rg)2+(aT)2
Fnet=1000(1600400)2+32=10316+9
Fnet=5000 N

Hence option 'c' is the correct answer

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