A car of mass 1000kg negotiates a banked curve of radius 90m on a frictionless road. If the banking angle is 45∘, the speed of the car is: Take g=10m/s2
A
20m/s
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B
30m/s
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C
15m/s
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D
25m/s
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Solution
The correct option is B30m/s Mass of car, m=1000kg Radius of curve, r=90m Banking angle, θ=45∘
The relation between permissible speed and banking angle is , tanθ=v2rg ⇒v=√rgtanθ ⇒v=√90×10×tan45∘ ⇒v=30m/s Speed of the car is 30m/s