A car of mass 1250 kg experience a resistance of 750 N when it moves at $30 m s^{- 1}$ . If the engine can develop 30kW at this speed, the maximum acceleration that the engine can produce is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

$P o w e r = F o r c e \times v e l o c i t y = (R e s i s t i v e f o r c e + A c c e l e r a t i n g f o r c e) \times v e l o c i t y$

$\Rightarrow 30 \times 10^{3} = (750 + m a) \times 30 \Rightarrow m a = 1000 - 750 \Rightarrow a = \frac{250}{1250} = 0.2 m s^{- 2}$

Suggest Corrections

Similar questions

A force of 2 kgf is applied on a body of mass 98 kg. Calculate the acceleration of the body. [ g = 9.8 m/s² = 980 cm/s²]

A car accelerates from rest to speed of 100 m/s in 10 seconds. If the mass of the car is 50 kg, then power developed by the engine is:

4 m s^{- 2}

6 m s^{- 2}

3 k m

20 m s^{- 1}

12

6

m / s^{2}

m / s^{2}

k m

Join BYJU'S Learning Program