A car of mass 1800 kg moves with a speed of 10 metre per second is brought to rest after covering distance of 50m calculate the applied force to the car

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Solution

Using third law of 1d kinematics,
v^2-u^2=2as
Given, s=50m; v=0; u=10m/s
Then , v^2-u^2=2as
0-(10)^2=2a(50)
a= -1m/s
Force=mass×acceleration, (or) Force=mass×deceleration
Therefore, deceleration= -1m/s^2
Deceleration= -(acceleration)
Force=mass×deceleration
=1800×1
=1800N
Force will be acting in opposite direction to displacement of the car

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