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Question

A car of mass 2000 kg is moving with a constant speed of 10 ms−1 on a circular path of radius 20 m on a level road. What must be the frictional force between the car and the road so that the car does not slip on the road ?

A
104 N
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B
103 N
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C
105 N
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D
102 N
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Solution

The correct option is A 104 N
To avoid slipping, frictional force will act in a direction to provide the necessary centripetal force. i.e frictional force will act towards centre of circular curvature.
Here,f is magnitude of frictional force.
f=mv2r
f=2000×10220=104 N

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