A car of mass 2000kg is moving with a constant speed of 10ms−1 on a circular path of radius 20m on a level road. What must be the frictional force between the car and the road so that the car does not slip on the road ?
A
104N
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B
103N
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C
105N
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D
102N
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Solution
The correct option is A104N To avoid slipping, frictional force will act in a direction to provide the necessary centripetal force. i.e frictional force will act towards centre of circular curvature.
Here,f is magnitude of frictional force. ∴f=mv2r f=2000×10220=104N