A car of mass 500 kg travelling with a speed of 20 m/s stops by applying wakes in 2 seconds. Find :-
Force applied by the wakes.
Work done by the wakes.

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Solution

Given,
$m = 500 g$
$U = 20 m / s$
$\begin{matrix} F = m a v^{2} - u^{2} = 20 s = m (\frac{Δ V}{t}) s = \frac{20 \times 20}{2 \times 10} = 20 m = 500 \times \frac{20}{2} = 5000 N w = f . x = 5000 \times 20 w = 100 k g \end{matrix}$

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A car of mass 500 kg travelling with a speed of 20 m/s stops by applying wakes in 2 seconds. Find :-Force applied by the wakes.Work done by the wakes.

Given,m=500gU=20m/sF=mav2−u2=20s=m(ΔVt)s=20×202×10=20m=500×202=5000Nw=f.x=5000×20w=100kg

A car of mass 500 kg travelling with a speed of 20 m/s stops by applying wakes in 2 seconds. Find :-
Force applied by the wakes.
Work done by the wakes.

Given,
$m = 500 g$
$U = 20 m / s$
$\begin{matrix} F = m a v^{2} - u^{2} = 20 s = m (\frac{Δ V}{t}) s = \frac{20 \times 20}{2 \times 10} = 20 m = 500 \times \frac{20}{2} = 5000 N w = f . x = 5000 \times 20 w = 100 k g \end{matrix}$