A car of mass m is driven with acceleration 'a' alone When the velocity of the car is V the rate at which the engine of the car is doig work will be :

R V

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m a V

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(R_{m}) V

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(m a + R) V

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Solution

The correct option is B $m a V$
Rate of work is nothing but $p o w e r$ delivered by engine at that moment.
Work $W = F . x$ , $x$ is displacement so power $P = \frac{d W}{d t} = \frac{m a . x}{d t} = m a \frac{d x}{d t} = m a V$

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A car of mass m is driven with acceleration 'a' alone When the velocity of the car is V the rate at which the engine of the car is doig work will be :

The correct option is B maVRate of work is nothing but power delivered by engine at that moment.Work W=F.x, x is displacement so power P=dWdt=ma.xdt=madxdt=maV

The correct option is B $m a V$
Rate of work is nothing but $p o w e r$ delivered by engine at that moment.
Work $W = F . x$ , $x$ is displacement so power $P = \frac{d W}{d t} = \frac{m a . x}{d t} = m a \frac{d x}{d t} = m a V$