A car of mass ′m′ is driven with acceleration ′a′ along a straight level road against a constant external resistive force ′R′. When the velocity of the car is ′V′, the rate at which the engine of the car is doing work will be
A
RV
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B
maV
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C
(R+ma)V
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D
(ma−R)V
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Solution
The correct option is C(R+ma)V Total force require to oppose the resistive force and move with acceleration a is, F=ma+R Power is given by, ∴P=(ma+R)V