A car of mass $m$ is driven with acceleration $a$ along a straight road against a constant external resistance $R$ . When the velocity is $v$ , the power of the engine is

R v

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m a v

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(R + m a) v

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(R - m a) v

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Solution

The correct option is C $(R + m a) v$
Total force developed by the car to move $= R + m a$
Power of the engine $= F . v = (R + m a) v$

Hence correct answer is option $C$

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A car of mass m is driven with acceleration a along a straight road against a constant external resistance R. When the velocity is v, the power of the engine is

The correct option is C (R+ma)vTotal force developed by the car to move =R+maPower of the engine =F.v=(R+ma)v Hence correct answer is option C

A car of mass $m$ is driven with acceleration $a$ along a straight road against a constant external resistance $R$ . When the velocity is $v$ , the power of the engine is

The correct option is C $(R + m a) v$
Total force developed by the car to move $= R + m a$
Power of the engine $= F . v = (R + m a) v$

Hence correct answer is option $C$