A car of mass m is driven with acceleration π along a straight level road against a constant external resistive force R. When the velocity of the car is V, the rate at which the engine of the car is doing work will be
A
(ma−R)V
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B
(R+ma)V
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C
maV
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D
RV
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Solution
The correct option is B(R+ma)V Formula Used: P=F.v
Given, mass of car =mkg
Acceleration =a
Resistive force =R
Velocity of car =V
As the power is given by, P=F.v
Force is required to oppose the resistive force Rand also to accelerate the body of mass with acceleration 𝑎. F−R=maF=R+maP=FV=(R+ma)V power(P)=(R+ma)V