A car passes a person standing on road, when car was approaching it, frequency received by person was n. When it recedes, the frequency received by the person is 3n/5, find speed of car. (Speed of sound = 330m/s)
A
60.4 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
82.5 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
32.8 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4.34 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 82.5 m/s By using doppler's effect we can say:
When car is approaching the person: n=n0{330−0330−x}
When car is receding the person: 3n5=n0{330−0330+x}n/3n/5=n0(/330(330−x))n0/330(330+x)=330+x330−x⇒53=330+x330−x