A car runs around a curve of radius $10$ m at a constant speed of $10$ Consider the time interval fro which car covers a curve if $120$ arc.

Open in App

Solution

Given $θ = 120$ and speed $v = 10 m / s$ and radius $r = 10 m$
We know Arc $= \frac{θ}{360} 2 π r = \frac{20 π}{3}$
Also time $t = \frac{s}{v} = \frac{20 π}{3 \times 10} = 1.09 s$

Suggest Corrections

Similar questions

A 1000-kg car travels along a straight 500-m portion of the highway (from A to B) at a constant speed of 10 m/s. At B, the car encounters an unbanked curve of radius 50 m. The car follows the road from B to C travelling at a constant speed of 10 m/s while the direction of the car changes from east to south. What is the magnitude of the frictional force (Centripetal force) between the tires and the road as the car negotiates the curve from B to C?

Q. An object of

60 kg-wt

is weighed by hanging it to the spring balance, from the ceiling of a car. If the car starts moving around a curve of radius

10 m

at a speed

10 {ms}^{- 1}

. The reading of the spring balance would be
[

1 kg-wt = 10 N

]

Two cars of masses M and 2M travel at the same speed around a banked curve, of radius r, which is covered with ice. If the first car negotiates the curve without slipping, the second car will :

Q. A flat curve on a highway has a radius of curvature

400 m

. A car goes around a curve at a speed of

32 m / s

. What is the minimum value of coefficient of friction that will prevent the car from sliding? (

g = 9.8 m / s^{2}

)

Q. A car of mass

1000 kg

negotiates a banked curve of radius

90 m

on a frictionless road. If the banking angle is

45^{\circ}

, the speed of the car is:
Take

g = 10 {m/s}^{2}

Join BYJU'S Learning Program

A car runs around a curve of radius 10 m at a constant speed of 10 Consider the time interval fro which car covers a curve if 120 arc.

Given θ=120 and speed v=10m/s and radius r=10mWe know Arc=θ3602πr=20π3Also timet=sv=20π3×10=1.09s

A car runs around a curve of radius $10$ m at a constant speed of $10$ Consider the time interval fro which car covers a curve if $120$ arc.

Given $θ = 120$ and speed $v = 10 m / s$ and radius $r = 10 m$
We know Arc $= \frac{θ}{360} 2 π r = \frac{20 π}{3}$
Also time $t = \frac{s}{v} = \frac{20 π}{3 \times 10} = 1.09 s$