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Question

A car skids a distance of 54m on a dry road. What was the velocity of the car when the skid began if the coefficient of friction between the tires and the road is .46?

A
16 m/s
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B
22 m/s
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C
28 m/s
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D
34 m/s
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E
Velocity cannot be determined with the information given
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Solution

The correct option is B 22 m/s
Given : μ=0.46
Let the mass and initial velocity of the car be m and u respectively.
Final velocity of the car is zero i.e v=0m/s
Skidding distance S=54 m
Thus frictional force f=μmg
Acceleration of the car a=μmgm=μg=0.46×9.8=4.5m/s2
Using v2u2=2aS
OR 0u2=2(4.5)×54 u=2×4.5×54=22 m/s

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