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Question

A car starting from rest accelerates at the rate f through a distance s1, and then decelerates at rate f2 through a distance s2 to come to rest. Then s1s2 is

A
12
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B
13
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C
14
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D
2
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Solution

The correct option is A 12
Velocity of the car varies with diplacement as

v2=u2+2ax

For accelerating part,

v2=02+2f×s1 ....(i)

For decelerating part,

02=v2+2(0.5f)×s2 ...(ii)

From (i) and (ii)

s1s2=12




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