A car starting from rest- is accelerated at a constant rate - until it attains a speed V - It is then retarded at a constant rate - until it comes to rest- The average speed of the car during its entire journey is -

The correct option is D v 2 The average speed is given as, #10; #10; v_avg = #10;st #10; #10; v_avg = #10;V^22α + V^22β #10;Vα + Vβ ...

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Standard IX

Physics

Acceleration

A car startin...

Question

A car starting from rest, is accelerated at a constant rate $α$ until it attains a speed $V$ . It is then retarded at a constant rate $β$ until it comes to rest. The average speed of the car during its entire journey is :

Zero

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\frac{α v}{2}

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\frac{β v}{2}

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\frac{v}{2}

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Solution

The correct option is D $\frac{v}{2}$
The average speed is given as,

$v_{a v g} = \frac{s}{t}$

$v_{a v g} = \frac{\frac{V^{2}}{2 α} + \frac{V^{2}}{2 β}}{\frac{V}{α} + \frac{V}{β}}$

$v_{a v g} = \frac{V}{2}$

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A car starting from rest, is accelerated at a constant rate α until it attains a speed V . It is then retarded at a constant rate β until it comes to rest. The average speed of the car during its entire journey is :

The correct option is D v2The average speed is given as, vavg=st vavg=V22α+V22βVα+Vβ vavg=V2

A car starting from rest, is accelerated at a constant rate $α$ until it attains a speed $V$ . It is then retarded at a constant rate $β$ until it comes to rest. The average speed of the car during its entire journey is :

The correct option is D $\frac{v}{2}$
The average speed is given as,

$v_{a v g} = \frac{s}{t}$

$v_{a v g} = \frac{\frac{V^{2}}{2 α} + \frac{V^{2}}{2 β}}{\frac{V}{α} + \frac{V}{β}}$

$v_{a v g} = \frac{V}{2}$