A car starts from rest and accelerated with uniform acceleration a1 -8203- nbsp-for 10 seconds then decelerated with uniform deceleration a2 nbsp-to finally come to rest in next 5 seconds- Show that a1-a2-1-2

For #160;first #160;10 #160;secondsu #160;= #160;0v #160;is #160;the #160;velocity #160;after #160;10 #160;st #160;= #160;10 #160;sv ...

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Byju's Answer

Standard XII

Physics

Finding Average Velocity

A car starts ...

Question

A car starts from rest and accelerated with uniform acceleration a₁ for 10 seconds then decelerated with uniform deceleration a₂to finally come to rest in next 5 seconds. Show that a_1/a₂=1/2

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Solution

$F o r f i r s t 10 s e c o n d s u = 0 v i s t h e v e l o c i t y a f t e r 10 s t = 10 s v = u + a_{1} t V = 0 + a_{1} \times 10 V = 10 a_{1} f o r n e t 5 s e c o n d s f i n a l v e l o c i t y i s z e r o t h e n 0 = v - a_{2} \times 5 v = a_{2} 5 f o r t h e s e t h w o q u e s t i o n a_{1} \times 10 = a_{2} \times 5 \frac{a_{1}}{a_{2}} = \frac{5}{10} = \frac{1}{2}$

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A car starts from rest and accelerated with uniform acceleration a1​ for 10 seconds then decelerated with uniform deceleration a2 to finally come to rest in next 5 seconds. Show that a1/a2=1/2

For first 10 secondsu = 0v is the velocity after 10 st = 10 sv = u +a1tV = 0+a1×10V = 10a1for net 5 secondsfinal velocity is zero then 0 = v -a2×5v = a25for these thwo questiona1×10= a2×5a1a2 = 510=12

A car starts from rest and accelerated with uniform acceleration a₁ for 10 seconds then decelerated with uniform deceleration a₂to finally come to rest in next 5 seconds. Show that a_1/a₂=1/2