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Question

A car starts from rest and accelerates uniformly to a speed of 90 km/h in 5 s. The distance covered by the car in this time interval is

A
125 m
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B
60 m
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C
62.5 m
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D
48 m
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Solution

The correct option is C 62.5 m
Given Final Speed, v=90 kmh1=25 ms1
Time taken t=5 s
Using first equation of motion, v=u+at
Acceleration of the car a=vut=2505(u=0 as body starts from rest)
=5 ms2
Thus, the distance covered by the car
S=ut+12at2 (Using second equation of motion)
S=0+12×5×(5)2
(u=0 as body starts from rest)
S=62.5 m

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