A car starts from rest and is uniformly accelerated to a speed of 30 m/s in 6s. What is the distance travelled by the car ?

5 m

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30 m

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90 m

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180 m

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Solution

The correct option is D 90 m
$s = u \times t + \frac{1}{2} \times a \times t^{2}$ -------(1)
$a = \frac{v - u}{t}$ -------(2)
where s is Distance travelled.
u is initial Speed.
v is final Speed.
a is Acceleration.
t is time.
Given : $u = 0, v = 30 \frac{m}{s}, t = 6 s e c$
$a = \frac{30}{6}$ using equ. (2)
$a = 5 \frac{m}{s^{2}}$
$s = 0 + \frac{1}{2} \times 5 \times 6^{2}$ using equ. (1)
$s = 90 m$

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A car starts from rest and is uniformly accelerated to a speed of 30 m/s in 6s. What is the distance travelled by the car ?

The correct option is D 90 ms=u×t+12×a×t2 -------(1)a=v−ut -------(2)where s is Distance travelled. u is initial Speed. v is final Speed. a is Acceleration. t is time.Given : u=0,v=30ms,t=6sec a=306 using equ. (2) a=5ms2 s=0+12×5×62 using equ. (1) s=90m