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Question

A car starts from rest and moves with uniform acceleration a on a straight road from time t=0 to t=T . After that, a constant deceleration brings it to rest. In this process the average speed of the car is

A
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C
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Solution

The correct option is C

For First part,

u = 0, t = T and acceleration = a
v=0+aT and S1=0+12aT2=12aT2

For second part,
u = aT, retardation = a1, v = 0 and time taken = T1(let)
0=ua1T1 aT=a1T1

and from v2=u22aS2 S2=u22a1=12 a2T2a1

S2=12aT×T1 (As a1=aTT1)

vav=S1+S2T+T1=12aT2+12aT×T1T+T1

=12aT(T+T1)T+T1=12aT


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