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Question

# A car starts from rest and moves with uniform acceleration a on a straight road from time t=0 to t=T . After that, a constant deceleration brings it to rest. In this process the average speed of the car is

A
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C
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Solution

## The correct option is C For First part, u = 0, t = T and acceleration = a ∴ v=0+aT and S1=0+12aT2=12aT2 For second part, u = aT, retardation = a1, v = 0 and time taken = T1(let) ∴ 0=u−a1T1 ⇒ aT=a1T1 and from v2=u2−2aS2 ⇒S2=u22a1=12 a2T2a1 S2=12aT×T1 (As a1=aTT1) ∴vav=S1+S2T+T1=12aT2+12aT×T1T+T1 =12aT(T+T1)T+T1=12aT

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