Given that,
Time t=10sec
Velocity v=12km/h=12×518m/s
Now, the acceleration is
Using of equation of motion
v=u+at
12×518=0+a×10
a=12×510×18
a=13m/s2
Hence, the acceleration is 13m/s2
A train starting from a railway station moves with uniform accrleration and attains a speed of 40km hr-1 in 10 minutes. Find its acceleration.