A car starts from rest, moves with an acceleration a and then decelerates at b for some time to come to rest. If the total time taken is t, the maximum velocity is
A
abta+b
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B
a2a+b
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C
ata+b
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D
b2a+b
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Solution
The correct option is Aabta+b Let t1 be the time for acceleration and t−t1 be the time for deceleration and v be maximum velocity. v=0+t1&0=v−b(t−t1)⇒at1=b(t−t1)⇒t1=bta+b⇒v=abta+b