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Question

A car starts from rest, moves with an acceleration a and then decelerates at b for some time to come to rest. If the total time taken is t, the maximum velocity is

A
abta+b
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B
a2a+b
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C
ata+b
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D
b2a+b
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Solution

The correct option is A abta+b
Let t1 be the time for acceleration and tt1 be the time for deceleration and v be maximum velocity.
v=0+t1&0=vb(tt1)at1=b(tt1)t1=bta+bv=abta+b

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