A car takes $60$ minutes less for a journey of $150 K m$ . If its speed is increased by $5$ Km per hour from its usual speed. Find the original speed of the car.

Open in App

Solution

Let the original speed of car = x km/h
Distance travelled by car = 150 km.
Time $(t_{1}) = \frac{150}{x}$
If speed is increased by 5 km/h then
Speed = (x+5) km/h
Distance = 150 km
Time $(t_{2}) = \frac{150}{x + 5}$
$t_{1} - t_{2} = 1$ [Given]
$\frac{150}{x} - \frac{150}{x + 5} = 1$
$150 x - 150 x + 750 = x^{2} + 5 x$
$x^{2} + 5 x - 750 = 0$
By spliting the middle team
$x^{2} + 30 x - 25 x - 750 = 0$
$x (x + 30) - 25 (x + 30) = 0$
$(x - 25) (x + 30) = 0$
$x = 25$ or $x = - 30$
As speed can't be negative so $x \neq - 30$
So, the usual speed of car = 25 km/h.

Suggest Corrections

Similar questions

A

train takes

2

hours less for a journey of

300 k m

if its speed is increased by

5 k m

h from its usual speed. Find the usual speed of the train.

A passenger train takes one hour less for a journey of 150km if its speed is increased by 5km/hr from its usual speed. Find the usual speed of the train.

A passenger train takes 2 hours less for a journey of 300 km if its speed is increased by 5 km/hr from its usual speed. Find its usual speed.

Q. A train takes 2 hours less for a journey of 300 km if its speed is increased by 5 km/h from its usual speed. Find the usual speed of the train

Q. A train takes

2 h o u r s

less for a journey of

300 k m

, if its speed is increased by

5 k m / h

from its usual speed. Find the usual speed of the train.

Join BYJU'S Learning Program

A car takes 60 minutes less for a journey of 150Km. If its speed is increased by 5 Km per hour from its usual speed. Find the original speed of the car.

A car takes $60$ minutes less for a journey of $150 K m$ . If its speed is increased by $5$ Km per hour from its usual speed. Find the original speed of the car.