A car travelling at $60 k m / h$ overtakes another car travelling at $42 k m / h$ . Assuming each car to be $5.0 m$ long, the time taken for the over taking is

6 s

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4 s

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3 s

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2 s

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Solution

The correct option is D $2 s$
Relative velocity $= 60 - 42 = 18 k m / h$
$v = \frac{18 \times 1000}{3600} = 5 m / s$
Distance to be covered $= 5 + 5 = 10 m = D$
Time taken $= \frac{D}{v} = \frac{10}{5} = 2 s e c$

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