a car travelling at 60 km/hr overtakes another car travelling at 42 km/hr .assuming each car to be five meter long , find the time taken taken during the overtake .

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Solution

$R e l a t i v e v e l o c i t y, = 60 - 42 = 18 K m / h r = 5 m e t / s e c D i s \tan c e = 10 m e t T i m e = \frac{10}{5} = 2 s e c$

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a car travelling at 60 km/hr overtakes another car travelling at 42 km/hr .assuming each car to be five meter long , find the time taken taken during the overtake .

Relative velocity,=60-42=18Km/hr=5met/secDistance=10metTime=105=2sec

$R e l a t i v e v e l o c i t y, = 60 - 42 = 18 K m / h r = 5 m e t / s e c D i s \tan c e = 10 m e t T i m e = \frac{10}{5} = 2 s e c$