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Question

A car travelling at a constant speed of 10 m/s on a straight road passes a point (origin) at time t=0, and 5 seconds later another car passes the same point travelling at 20 m/s in the same direction.
The time t (from starting time) and distance from origin x, when second car overtakes first?

A
t=10 seconds
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B
x=100 meter
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C
t=8 seconds
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D
x=80 meter
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Solution

The correct options are
A t=10 seconds
C x=100 meter
distance traveled with constant velocity S=v.t
1st car travels S1=10t
second car starts after 5 s therefore
S2=20(t5)
when they meet both distance traveled by cars should be equal
10t=20(t5)
t=10s
S1=S2=100meters

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