By travelling at a speed of $48 k m / h$ , a car can finish a certain journey in $10$ hours. To cover the same distance in $8$ hours, the speed of the car should be

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A car travelling at a speed of 30km/hour is brought to a halt in 8 m by applying brakes. If the same car is travelling at 60km/hour, it can be brought to a halt with the same braking force in

The correct option is C 32mIt is know that v2=u2+2assince car is going to stop so v=0u2=−2ass∝u2 i.e if speed becomes double then stopping distance will become four times i.e.8×4=32m

A car travelling at a speed of $30 k m / h o u r$ is brought to a halt in 8 m by applying brakes. If the same car is travelling at $60 k m / h o u r$ , it can be brought to a halt with the same braking force in

The correct option is C $32 m$
It is know that $v^{2} = u^{2} + 2 a s$
since car is going to stop so $v = 0$
$u^{2} = - 2 a s$
$s \propto u^{2}$ i.e
if speed becomes double then stopping distance will become four times $i . e . 8 \times 4 = 32 m$