A car travels 30 km at the uniform speed of 40 km/h and next 30 km at the speed of 20 km/h. Find its average speed.

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Solution

The total time for the journey is given as,

$t = \frac{d_{1}}{v_{1}} + \frac{d_{2}}{v_{2}}$

$= \frac{30}{40} + \frac{30}{20}$

$= 2.25 h o u r$

The average speed is given as,

$v_{a v g} = \frac{d_{1} + d_{2}}{t}$

$= \frac{30 + 30}{2.25}$

$= 26.67 k m / h$

Thus, the average speed of the car is $26.67 k m / h$ .

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A car travels 30 km at the uniform speed of 40 km/h and next 30 km at the speed of 20 km/h. Find its average speed.

The total time for the journey is given as, t=d1v1+d2v2 =3040+3020 =2.25hour The average speed is given as, vavg=d1+d2t =30+302.25 =26.67km/h Thus, the average speed of the car is 26.67km/h.