A car travels $6.0 k m$ along a main road in $6.0$ minutes. It then travels $2.0 k m$ along a minor road in $6.0$ minutes. Which calculation of average speed for the whole journey is correct?

8.0 \div 12.0 = 0.67 k m / m i n u t e

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12.0 \div 8.0 = 1.57 k m / m i n u t e

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8.0 + 12.0 = 20 k m / m i n u t e

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8.0 \times 12.0 = 96 k m / m i n u t e

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Solution

The correct option is A $8.0 \div 12.0 = 0.67 k m / m i n u t e$
Total distance traveled is $8 + 2 k m$
Total time taken is $6 + 6 m i n$
Average speed is $= \frac{8}{12} = \frac{2}{3} = 0.67 k m / m i n$

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