A car travels a distance 100 m with a constant acceleration and average velocity of 20 $m s^{- 1}$ .The final velocity acquired by the car is 25 $m s^{- 1}$ .Find:(i) the initial velocity and (ii) acceleration of car.

Open in App

Solution

Given,
Total distance (s) = 100m
Average velocity = 20m/s
Final velocity (v) = 25m/s

(1)
We know,
Average velocity = $\frac{u + v}{2}$
=> 20 = $\frac{u + 25}{2}$
=> u = 15

Therefore,
The initial velocity is 15m/s

(2)
Acceleration (a) = ?

Using the 3rd equation of uniform motion,

2as = v² - u²
2(a)(100) = (25)²-(15)²
200a = 400
a = 400/200
=> a = 2

Thus,
The acceleration is 2m/s²

Suggest Corrections

Similar questions

Q. A car travels a distance

100 m

with a constant acceleration and average velocity of

20 m s^{- 1}

. The final velocity acquired by the car is

25 m s^{- 1}

. Find the initial velocity.

A car travels a distance of 100 m with a constant acceleration and average velocity of 20 m/s the final velocity acquired by the car race is 25 m/s find the initial velocity and acceleration.

Q. A car initially at rest starts moving with a constant acceleration of

0.5 m s^{- 2}

and travels a distance of

25 m

. Find the final velocity.

Q. A car moving with initial velocity of

10 m s^{- 1}

attains a speed, v in 5 seconds. The car travels a distance of 100 m. Find v.

Q. A car at rest accelerates uniformly at the rate of

4 m / s^{2}

through a distance of

100 m .

Find its final velocity and average velocity.

Join BYJU'S Learning Program

Explore more

The Equations of Motion

Standard IX Physics

Join BYJU'S Learning Program

A car travels a distance 100 m with a constant acceleration and average velocity of 20 m s−1.The final velocity acquired by the car is 25 m s−1.Find:(i) the initial velocity and (ii) acceleration of car.

A car travels a distance 100 m with a constant acceleration and average velocity of 20 $m s^{- 1}$ .The final velocity acquired by the car is 25 $m s^{- 1}$ .Find:(i) the initial velocity and (ii) acceleration of car.