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Standard IX

Physics

Velocity(Speed with Direction)

A car travels...

Question

A car travels a distance 50 km with a velocity $25 k m h^{- 1}$ and then 60 km with a velocity $20 k m h^{- 1}$ in the same direction. Calculate the average velocity of the car.

11 k m h^{- 1}

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22.5 k m h^{- 1}

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22 k m h^{- 1}

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45 k m h^{- 1}

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Solution

The correct option is C $22 k m h^{- 1}$
Total distance travelled $S = S_{1} + S_{2}$
$= 50 k m + 60 k m = 110 k m$
Total time $t = t_{1} + t_{2}$
$t = \frac{s_{1}}{v_{1}} + \frac{s_{2}}{v_{2}}$

$= \frac{50}{25} + \frac{60}{20} = 5 h$

Average velocity $= \frac{Total distance travelled S}{Total time of journey t}$
$= \frac{110 k m}{5 h} = 22 k m h^{- 1}$

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A car travels a distance 50 km with a velocity 25 kmh−1 and then 60 km with a velocity 20 kmh−1 in the same direction. Calculate the average velocity of the car.

The correct option is C 22 kmh−1Total distance travelled S=S1+S2 =50km+60km=110kmTotal time t=t1+t2t=s1v1+s2v2 =5025+6020=5 hAverage velocity =Total distance travelled STotal time of journey t=110km5h=22 kmh−1

A car travels a distance 50 km with a velocity $25 k m h^{- 1}$ and then 60 km with a velocity $20 k m h^{- 1}$ in the same direction. Calculate the average velocity of the car.