A car travels a distance $50 k m$ with a velocity $25 k m h^{- 1}$ and then $60 k m$ with a velocity $20 k m h^{- 1}$ in the same direction. Calculate the total time of journey.

10 h

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5 h

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1 h

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25 h

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Solution

The correct option is A $5 h$
TIme of Journey $t = \frac{D i s t a n c e (S)}{v e l o c i t y (v)}$

$∴ t_{1} = \frac{s_{1}}{v_{1}} = \frac{50 k m}{25 k m h^{- 1}} = 2 h$

$t_{2} = \frac{S_{2}}{v_{2}} = \frac{60 k m}{20 k m h^{- 1}} = 3 h$

Total time of journey $t = t_{1} + t_{2} = 2 h + 3 h = 5 h$

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