Question

A car travels at a speed of $40m{s}^{-1}$ for the first 2 seconds and $60m{s}^{-1}$ for the next 4 seconds. The distance travelled by the car is:

• A. 240 m
• B. 280 m
• C. 320 m
• D. 360 m

Answer 1

The correct option is C 320 m

Given:
Distance travelled by the car in $t_1=2s$ is $d_1$
In this case, speed $v_1=40m{s}^{-1}$
Distance travelled by the car in $t_2=4s$ is $d_2$
In this case, speed $v_2=60m{s}^{-1}$
We know that,
Distance travelled = Speed x Time
$d_1=40x2=80m$
$d_2=60x4=240m$
Total distance travelled $=d_1+d_2=240+80=320m$