A car travels at a speed of 60 m/s for first 3 seconds and 40 m/s for the next 2 seconds. The total distance travelled by the car in those 5 seconds is:

300 m

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200 m

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260 m

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160 m

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Solution

The correct option is C 260 m
$Distance = Speed \times Time$

The distance travelled in the first 3 seconds,
$d_{1} = 60 m / s \times 3 s$
$d_{1} = 180 m$

The distance travelled in the next 2 seconds,
$d_{2} = 40 m / s \times 2 s$
$d_{2} = 80 m$

Hence, the total distance travelled by the car,
$d = 180 m + 80 m$
$d = 260 m$

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