A car travels first $30 k m$ with a uniform speed of $60 k m p h$ and then next $30 k m$ with a uniform speed of $40 k m p h$ . Calculate the total time of journey.

15 m i n

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30 m i n

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60 m i n

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75 m i n

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Solution

The correct option is D $75 m i n$
Time for first part = $t_{1}$ = $\frac{30}{60} h r = 0.5 h r = 30 m i n$

Time for second part = $t_{2}$ = $\frac{30}{40} h r = 0.75 h r = 45 m i n$

$∴$ total time = $t_{1} + t_{2}$ $= (30 + 45) m i n = 75 m i n$

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A train travels the first 15 km at a uniform speed of 30 km/h; the next 75 km at a uniform speed of 50 km/h; and the last 10 km at a uniform speed of 20 km/h. Calculate the average speed for the entire train journey.

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A car travels first 30km with a uniform speed of 60kmph and then next 30km with a uniform speed of 40kmph. Calculate the total time of journey.

The correct option is D 75 minTime for first part = t1 = 3060hr=0.5hr=30 minTime for second part = t2 = 3040hr=0.75hr=45 min∴ total time = t1+t2=(30+45) min=75 min

A car travels first $30 k m$ with a uniform speed of $60 k m p h$ and then next $30 k m$ with a uniform speed of $40 k m p h$ . Calculate the total time of journey.

The correct option is D $75 m i n$
Time for first part = $t_{1}$ = $\frac{30}{60} h r = 0.5 h r = 30 m i n$

Time for second part = $t_{2}$ = $\frac{30}{40} h r = 0.75 h r = 45 m i n$

$∴$ total time = $t_{1} + t_{2}$ $= (30 + 45) m i n = 75 m i n$