A car travels from point A to point B which are 160 km apart in 3 hours. The car comes back to point A in 2 hours, then the average speed of the car in km/h is

0 km/h

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20 km/h

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32 km/h

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64 km/h

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Solution

The correct option is D 64 km/h
The car travels from 'A' to 'B' and returns to the point 'A'.
$∴$ The total distance covered = 160 + 160 = 320 km
Total time taken for the entire journey = 3 + 2 = 5 h.
We know, $A v e r a g e s p e e d = \frac{t o t a l d i s t a n c e}{t o t a l t i m e}$
$= \frac{320}{5}$
$= 64 k m h^{- 1}$

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A car travels from point A to point B which are 160 km apart in 3 hours. The car comes back to point A in 2 hours, then the average speed of the car in km/h is

The correct option is D 64 km/hThe car travels from 'A' to 'B' and returns to the point 'A'. ∴ The total distance covered = 160 + 160 = 320 km Total time taken for the entire journey = 3 + 2 = 5 h. We know, Average speed=total distancetotal time =3205 =64kmh−1