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Question

# A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find :(a) displacement of the car (b) The average speed of the carA(c) Total distance traveled

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Solution

## Step 1: GivenSpeed from A to B = 30 km/hSpeed from B to A = 50 km/hLet the distance between the A and B be X.Step 2: Formula usedAveragespeed=TotaldistancetraveledTotaltimetaken speed=distancetimetaken Part (a)Step 3: Finding the displacementSince the car travels back to the same position A, its displacement is zero.Displacement is defined as the shortest distance between the initial and final position.In this case, the initial position and final position of the car is the same so displacement is zero.Part (b)Step 4: Finding the average speedTime taken by the car to travel from the A to B = X30 hTime taken by the car to travel from B to A = X50 hWe know,Averagespeed=TotaldistancetraveledTotaltimetaken Putting all the valuesAveragespeed=2X(X30+X50) After solvingAverage speed = 37.5 km/hPart (c) Step 5: Finding the total distanceTotal distance traveled by car = 2×37.5=75mHence, the total distance covered by car is 75m.

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