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Question

A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find :

(a) displacement of the car

(b) The average speed of the carA

(c) Total distance traveled

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Solution

Step 1: Given

Speed from A to B = 30 km/h

Speed from B to A = 50 km/h

Let the distance between the A and B be X.

Step 2: Formula used

Averagespeed=TotaldistancetraveledTotaltimetaken

speed=distancetimetaken

Part (a)

Step 3: Finding the displacement

Since the car travels back to the same position A, its displacement is zero.

Displacement is defined as the shortest distance between the initial and final position.

In this case, the initial position and final position of the car is the same so displacement is zero.

Part (b)

Step 4: Finding the average speed

Time taken by the car to travel from the A to B = X30 h

Time taken by the car to travel from B to A = X50 h

We know,

Averagespeed=TotaldistancetraveledTotaltimetaken

Putting all the values

Averagespeed=2X(X30+X50)

After solving

Average speed = 37.5 km/h

Part (c)

Step 5: Finding the total distance

Total distance traveled by car = 2×37.5=75m

Hence, the total distance covered by car is 75m.


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