a car travels how the distance with constant velocity of 40 kilometre per hour and the remaining half with a constant velocity of 60 km per hour find the average velocity of the car in kilometre per hour

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Solution

$D e a r S t u d e n t, V_{a v g} = \frac{2 V_{1} V_{2}}{V_{1} + V_{2}} V_{a v g} = \frac{2 \times 40 \times 60}{40 + 60} V_{a v g} = \frac{4800}{100} = 48 k m / h r R e g a r d s$

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a car travels how the distance with constant velocity of 40 kilometre per hour and the remaining half with a constant velocity of 60 km per hour find the average velocity of the car in kilometre per hour

Dear Student ,Vavg=2V1V2V1+V2Vavg=2×40×6040+60Vavg=4800100=48km/hrRegards

$D e a r S t u d e n t, V_{a v g} = \frac{2 V_{1} V_{2}}{V_{1} + V_{2}} V_{a v g} = \frac{2 \times 40 \times 60}{40 + 60} V_{a v g} = \frac{4800}{100} = 48 k m / h r R e g a r d s$