A car travels on a straight road from point $A$ to point $B$ in four hours, and then from point $B$ back to point $A$ in six hours. The distance between the two points is $240 k m$ .
What is the car's average speed?

0 k m / h

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48 k m / h

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50 k m / h

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60 k m / h

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100 k m / h

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Solution

The correct option is A $48 k m / h$
Total distance traveled by car $D = 240 + 240 = 480$ km
Total time taken $t = 4 + 6 = 10$ h
$∴$ Average speed of car $= \frac{D}{t} = \frac{480}{10} = 48$ $k m / h$

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A car travels on a straight road from point A to point B in four hours, and then from point B back to point A in six hours. The distance between the two points is 240km.What is the car's average speed?

The correct option is A 48km/hTotal distance traveled by car D=240+240=480 kmTotal time taken t=4+6=10 h∴ Average speed of car =Dt=48010=48 km/h

A car travels on a straight road from point $A$ to point $B$ in four hours, and then from point $B$ back to point $A$ in six hours. The distance between the two points is $240 k m$ .
What is the car's average speed?

The correct option is A $48 k m / h$
Total distance traveled by car $D = 240 + 240 = 480$ km
Total time taken $t = 4 + 6 = 10$ h
$∴$ Average speed of car $= \frac{D}{t} = \frac{480}{10} = 48$ $k m / h$