A car travels on paths A, B, and C within the same time duration and has average velocities $v_{A}, v_{B}, a n d v_{c},$ respectively. These paths pass through a group of equally spaced lines. Identify the average velocities of the car in the respective order.

v_{A} = v_{B} = v_{C}

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v_{A} > v_{B} < v_{C}

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v_{A} > v_{B} > v_{C}

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v_{A} < v_{B} < v_{C}

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Solution

The correct option is A $v_{A} = v_{B} = v_{C}$
$Average velocity = \frac{Total displacement}{Total time}$
Therefore, $v_{A} = v_{B} = v_{C}$

The time taken to cover all the paths is the same.
So,
Average velocity ∝ Total displacement
Displacement for path A = Displacement for path B = Displacement for path C
As the displacement and time are the same for all the paths, the average velocities will also be the same.

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A car travels on paths A, B, and C within the same time duration and has average velocities vA,vB, and vc, respectively. These paths pass through a group of equally spaced lines. Identify the average velocities of the car in the respective order.

A car travels on paths A, B, and C within the same time duration and has average velocities $v_{A}, v_{B}, a n d v_{c},$ respectively. These paths pass through a group of equally spaced lines. Identify the average velocities of the car in the respective order.