wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car travels with the speed of 15 m/s for 0<t5 sec, 20 m/s for 5<t10 sec and 5 m/s for 10<t15 sec. The total distance travelled by the car is

A
250 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
150 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 200 m
For constant speed distance travelled is given by s=vt
So, for each time interval the distance travelled by the car is
s1=15×(50)=75 m
s2=20×(105)=100 m
s3=5×(1510)=25 m
Hence, total distance travelled by the car is 75+100+25=200 m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance and Displacement
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon