A car was moving at $1 m s^{- 1}$ and is brought to rest in $10 s$ by applying brakes. Calculate the retardation of the car.

0.1 m s^{- 2}

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1 m s^{- 2}

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0.01 m s^{- 2}

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None of these

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Solution

The correct option is B $0.1 m s^{- 2}$
$r e t a r d a t i o n = \frac{i n i t i a l v e l o c i t y - f i n a l v e l o c i t y}{t i m e}$
Initial velocity $= 1 m s^{- 1}$
Final velocity $= 0$
Time $= 10 s$
$∴$ $r e t a r d a t i o n = \frac{i n i t i a l v e l o c i t y - f i n a l v e l o c i t y}{t i m e} = \frac{1 - 0}{10} m s^{- 2} = 0.1 m s^{- 2}$

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