A car was moving at a speed of 12m-s- On applying brakes- it produced a deceleration of 6m-s2 and stopped- Calculate the distance traveled by car before stopping-

Initial velocity, u = 12m/s Final veloctiy, nbsp;v = nbsp;0m/s nbsp; accelaration, a = 6m/s2 S = ? nbsp; Applying 3rd equation of motion: v2 nbsp; ...

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Standard IX

Physics

Derivation of Position-Velocity Relation by Graphical Method

A car was mov...

Question

A car was moving at a speed of 12m/s. On applying brakes, it produced a deceleration of 6m/s² and stopped. Calculate the distance traveled by car before stopping.

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Solution

Initial velocity, u = 12m/s
Final veloctiy, v = 0m/s
accelaration, a = -6m/s²
S = ?

Applying 3rd equation of motion:
$v^{2} = u^{2} + 2 a s$
$0 = 12^{2} + 2 (- 6) s$

S = 12 meter.

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A car was moving at a speed of 12m/s. On applying brakes, it produced a deceleration of 6m/s2 and stopped. Calculate the distance traveled by car before stopping.

Initial velocity, u = 12m/s Final veloctiy, v = 0m/s accelaration, a = -6m/s2 S = ? Applying 3rd equation of motion: v2 = u2 + 2as 0 = 122 + 2(−6)s S = 12 meter.

A car was moving at a speed of 12m/s. On applying brakes, it produced a deceleration of 6m/s² and stopped. Calculate the distance traveled by car before stopping.

Initial velocity, u = 12m/s
Final veloctiy, v = 0m/s
accelaration, a = -6m/s²
S = ?

Applying 3rd equation of motion:
$v^{2} = u^{2} + 2 a s$
$0 = 12^{2} + 2 (- 6) s$

S = 12 meter.